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Math I

Real Numbers: Radicals and Rationalizing Denominators

Working with radicals comes down to simplifying what is inside and clearing radicals from denominators. Symmetric expressions make complicated values quick to compute.

Basic, Standard, Advanced: Grade 10 · Term 1

Math problem generator

Level

Simplifying radicals and rationalizing

For a,b>0a, b > 0, ab=ab\sqrt{a}\sqrt{b} = \sqrt{ab} and k2a=ka\sqrt{k^2 a} = k\sqrt{a}. Simplify each radical first, then combine like radicals.

Example: 12+27−48=23+33−43=3\sqrt{12} + \sqrt{27} - \sqrt{48} = 2\sqrt{3} + 3\sqrt{3} - 4\sqrt{3} = \sqrt{3}

Rationalizing
1a=aa,1a+b=a−ba−b\frac{1}{\sqrt{a}} = \frac{\sqrt{a}}{a},\qquad \frac{1}{\sqrt{a} + \sqrt{b}} = \frac{\sqrt{a} - \sqrt{b}}{a - b}

When the denominator is a sum or difference, use (a+b)(a−b)=a2−b2(a + b)(a - b) = a^2 - b^2 to remove the radical. Final answers should have no radical in the denominator.

Nested radicals and absolute values

Denesting
(a+b)+2ab=a+b,(a+b)−2ab=a−b(a>b>0)\sqrt{(a + b) + 2\sqrt{ab}} = \sqrt{a} + \sqrt{b},\qquad \sqrt{(a + b) - 2\sqrt{ab}} = \sqrt{a} - \sqrt{b}\quad (a > b > 0)

Look for two numbers with sum a+ba + b and product abab. If there is no factor 2, as in 4+15\sqrt{4 + \sqrt{15}}, rewrite the inside as 8+2152\frac{8 + 2\sqrt{15}}{2} first.

Absolute value: ∣a∣=a|a| = a if a≧0a \geqq 0 and ∣a∣=−a|a| = -a if a<0a < 0. Also a2=∣a∣\sqrt{a^2} = |a|, so (x−1)2\sqrt{(x - 1)^2} equals x−1x - 1 or 1−x1 - x depending on xx.

Integer and fractional parts; symmetric values

Since 2<7<32 < \sqrt{7} < 3, the integer part of 7\sqrt{7} is 2 and the fractional part is 7−2\sqrt{7} - 2 (the number minus its integer part).

If x+1x=kx + \frac{1}{x} = k, then

x2+1x2=(x+1x)2−2=k2−2x^2 + \frac{1}{x^2} = \left(x + \frac{1}{x}\right)^2 - 2 = k^2 - 2
Tip

For values such as x=3+2x = \sqrt{3} + \sqrt{2}, y=3−2y = \sqrt{3} - \sqrt{2}, first find x+yx + y and xyxy, then express what you need in terms of them.