Teleport

Main features

On this page

Topics

Arithmetic drills
Grade 7
Grade 8
Grade 9
Math I
Math A
Math II
Math B
Math C
Math III
Calculus
Linear algebra
Differential equations

Display

Theme
Math A

Properties of Figures: Practice Problems and Methods

The key to geometry problems is spotting which theorem the figure calls for. Master the ratio theorems (angle bisector, Ceva, Menelaus) and the circle theorems (inscribed angles, power of a point).

Basic, Standard: Grade 10 · Term 3 / Advanced: Grade 12 · Exam prep

Math problem generator

Level

Triangle properties and centers

Angle bisector theorem

If the bisector of ∠A\angle A meets BC at D, then BD:DC=AB:ACBD : DC = AB : AC.

The centroid G divides each median 2:12 : 1. The incenter I is where the angle bisectors meet, and ∠BIC=90∘+12∠A\angle BIC = 90^\circ + \frac{1}{2}\angle A. The circumcenter O is the center of the circumcircle; for an acute triangle ∠BOC=2∠A\angle BOC = 2\angle A. At the orthocenter H, ∠BHC=180∘−∠A\angle BHC = 180^\circ - \angle A.

Ceva's and Menelaus' theorems

Ceva and Menelaus
ARRB⋅BPPC⋅CQQA=1\frac{AR}{RB} \cdot \frac{BP}{PC} \cdot \frac{CQ}{QA} = 1

Ceva's theorem holds when three lines from the vertices meet at a point; Menelaus' theorem holds when one straight line cuts the three sides (or their extensions).

For Menelaus, go around the triangle "vertex → point → vertex → …" multiplying ratios. The main decision is which triangle and which line to use. For area ratios, use base ratios when heights are equal, and products of sides when an angle is shared.

Circles, the power of a point, constructions

An inscribed angle is half the central angle on the same arc. Opposite angles of a cyclic quadrilateral add to 180∘180^\circ. The angle between a tangent and a chord equals the inscribed angle on the arc inside it (tangent-chord theorem).

Power of a point
PA⋅PB=PC⋅PD,PT2=PA⋅PB(PT tangent)PA \cdot PB = PC \cdot PD,\qquad PT^2 = PA \cdot PB\quad (PT \text{ tangent})

Two circles are classified by comparing the distance between centers dd with the sum and difference of the radii. Constructions combine perpendicular bisectors, angle bisectors and parallel lines, for example to divide a segment or to construct a length ab\sqrt{ab}. Polyhedra satisfy Euler's formula v−e+f=2v - e + f = 2.