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Grade 9

The Pythagorean theorem: practice problems

In a right triangle a2+b2=c2a^2 + b^2 = c^2. Find a right triangle in the figure and many lengths follow.

Basic, Standard, Advanced: Grade 9 · Term 3

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Level

The theorem and its converse

Pythagorean theorem
a2+b2=c2a^2 + b^2 = c^2

Conversely, if a2+b2=c2a^2 + b^2 = c^2 the triangle is right-angled. Common triples: 3:4:53:4:5, 5:12:135:12:13, 8:15:178:15:17.

Special right triangles

A right isosceles triangle has sides in the ratio 1:1:21 : 1 : \sqrt{2}; a 30∘30^\circ–60∘60^\circ–90∘90^\circ triangle has 1:2:31 : 2 : \sqrt{3}. An equilateral triangle of side aa has height 32a\frac{\sqrt{3}}{2}a.

Applications

  • Distance: (x2−x1)2+(y2−y1)2\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
  • Chords: the perpendicular from the centre bisects a chord; a tangent is perpendicular to the radius.
  • Cuboid diagonal: a2+b2+c2\sqrt{a^2 + b^2 + c^2}
  • Cones and pyramids: use the right triangle formed by the height and a slant edge.
Shortest paths

Unfold the surface into a net; the shortest path is a straight segment.