Plane figures practice: sectors, transformations and constructions
For sectors, ask what fraction of the whole circle you have. For constructions, understand why each step works.
Basic, Standard, Advanced: Grade 7 · Term 3
Math problem generator
Arc length and sector area
Example: radius cm and angle give arc length cm and area cm.
Shaded areas
Write the shaded region as sums and differences of squares, sectors and triangles. Leave in the answer, for example .
Transformations
- Translation: every point moves the same distance in the same direction.
- Reflection in the -axis changes the sign of the -coordinate.
- Rotation about the origin: takes to ; anticlockwise takes to .
Basic constructions
- Perpendicular bisector: equal circles centred at both ends; join the two intersections. It is the set of points equidistant from both ends.
- Angle bisector: a circle centred at the vertex meets the sides; equal circles from those points meet on the bisector. It is the set of points equidistant from both sides.
- Perpendicular from a point: a circle centred at the point meets the line twice; equal circles from those points give a second point on the perpendicular.
Worked examples
Find the area of a sector with radius 5 cm and central angle 36°.
Hint
Sector area = , where is the central angle.
Answer
Solution
It is of the area of the circle.
Inside a square of side 10 cm, two semicircles are drawn on opposite sides as diameters. Find the area of the shaded region.
Hint
Express the shaded region as sums and differences of squares, sectors and triangles.
Answer
Solution
Two semicircles make one circle of radius cm. Subtract it from the square.
Construct the bisector of angle AOB.
Hint
Points equidistant from the two sides of an angle lie on its bisector.
Answer
(1) Draw a circle with centre O meeting OA at C and OB at D. (2) With centres C and D, draw circles with the same radius meeting at E. (3) Draw ray OE. It bisects angle AOB.
Solution
Since OC = OD and CE = DE, quadrilateral OCED is symmetric about line OE, so OE splits angle AOB into two equal angles.
Practice problems
Find the circumference and the area of a circle with radius 11 cm.
Hint
A circle of radius has circumference and area .
Answer
- circumference
- area
Solution
Circumference
Area
Find the perimeter of a sector with radius 9 cm and central angle 40°.
Hint
The perimeter of a sector is the arc length plus two radii.
Answer
Solution
Arc length:
Add the two radii.
Construct the point P on side BC of triangle ABC that is the same distance from sides AB and AC.
Hint
Points equidistant from two sides lie on the bisector of the angle between them.
Answer
(1) Construct the bisector of angle BAC (draw a circle centred at A, then equal circles centred where it meets AB and AC, and join A to their intersection). (2) The bisector meets BC at P.
Solution
Every point on the bisector of angle BAC is equidistant from AB and AC; the one on BC is P.