Exponential and logarithmic functions: practice problems
Exponents and logarithms are two views of the same relation: . Build fluency with the rules and with solving equations and inequalities.
Basic, Standard: Grade 11 · Term 2 / Advanced: Grade 12 · Exam prep
Math problem generator
Exponent laws and roots
Write everything as powers of the same base. Example: .
To compare numbers, use a common base: if the base is greater than , a larger exponent gives a larger number (the reverse if the base is less than ).
Logarithm rules and change of base
Example: .
Equations and inequalities
For exponential equations, write both sides as powers of the same base and compare exponents. For , substitute ().
For logarithmic equations and inequalities, first require the arguments to be positive. Example: needs ; then gives ( is rejected).
If , inequalities reverse: and .
Common logarithms and digits
A positive integer has digits exactly when , i.e. .
Example: with , , so has digits. Since the fractional part is less than , the leading digit is .
For : if , the first non-zero digit is at the -th decimal place.
Worked examples
Choose the correct ordering of the three numbers.
- A
- B
- C
- D
Hint
Write each number as ; since the base , a larger exponent gives a larger number.
Answer
Solution
As powers of ,
Since the base , the order of the numbers matches the order of the exponents:
Let and . Express in terms of and .
Hint
Change to base , then write as a product or quotient of , and .
Answer
Solution
By the change-of-base formula,
Expressing in terms of and ,
Hence
Solve the inequality.
Hint
Put () and solve the quadratic inequality in .
Answer
Solution
Put with :
Together with ,
Since the base ,
Practice problems
Evaluate.
Hint
Use and the laws , .
Answer
Solution
Since ,
Solve the equation.
Hint
First find where both arguments are positive, then combine the logs into one.
Answer
Solution
The arguments must be positive:
Combining the left side,
Simplifying and solving,
Since ,
For , find the maximum and minimum values of and the values of at which they occur.
Hint
Put ; then is a quadratic in . Watch the range of .
Answer
- Maximum
- x at the maximum
- Minimum
- x at the minimum
Solution
Put . From ,
In terms of ,
The minimum occurs at () and the maximum at .