Derivatives and tangent lines: practice problems
The derivative is the instantaneous rate of change and the slope of the tangent line. Learn the definition, how to differentiate polynomials and how to find tangent lines.
Basic, Standard, Advanced: Grade 11 · Term 3
Math problem generator
Average rate of change and the derivative
The average rate of change from to is , the slope of the chord.
Example: for , , so .
Limits such as are handled by subtracting and adding , giving .
Differentiating polynomials
Differentiate term by term; expand products such as first. Example: .
The same rules apply to other variables: the area of a circle has , the circumference.
Tangent and normal lines
At the point on :
For a tangent drawn from a point not on the curve, let the point of contact be at , write the tangent, and require it to pass through the given point.
Eliminating between a cubic and its tangent at gives a cubic equation with the factor ; the remaining factor gives the other common point.
Worked examples
Differentiate with respect to .
Hint
Treat letters other than as constants and use .
Answer
Solution
Differentiating with respect to ,
Find the equation of the normal to the curve at the point .
Hint
The normal is perpendicular to the tangent, so its slope is .
Answer
Solution
Since , the tangent slope is
The normal slope is
So the normal is
The curve passes through , and the tangent there has slope . Find , and the equation of the tangent.
Hint
The slope is at .
Answer
- a, b
- Tangent
Solution
Since , the slope condition gives
Since the curve passes through the point,
The tangent is
Practice problems
For , find the derivative and the value .
Hint
Use and term by term.
Answer
- f'(x)
- f'(0)
Solution
Differentiating term by term,
Substituting ,
The quadratic satisfies the following conditions. Find , and .
Hint
Substitute the conditions into and to get simultaneous equations.
Answer
Solution
Since , the conditions give
Solving,
The curve passes through , and the tangent there has slope . Find , and the equation of the tangent.
Hint
The slope is at .
Answer
- a, b
- Tangent
Solution
Since , the slope condition gives
Since the curve passes through the point,
The tangent is