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Math II

Derivatives and tangent lines: practice problems

The derivative is the instantaneous rate of change and the slope of the tangent line. Learn the definition, how to differentiate polynomials and how to find tangent lines.

Basic, Standard, Advanced: Grade 11 · Term 3

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Average rate of change and the derivative

The average rate of change from x=ax = a to x=bx = b is f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}, the slope of the chord.

Definition of the derivative
f′(a)=lim⁡h→0f(a+h)−f(a)h,f′(x)=lim⁡h→0f(x+h)−f(x)hf'(a) = \lim_{h \to 0}\frac{f(a + h) - f(a)}{h},\qquad f'(x) = \lim_{h \to 0}\frac{f(x + h) - f(x)}{h}

Example: for f(x)=x2f(x) = x^2, f(1+h)−f(1)h=2+h→2\frac{f(1 + h) - f(1)}{h} = 2 + h \to 2, so f′(1)=2f'(1) = 2.

Limits such as lim⁡h→0f(a+2h)−f(a−h)h\lim_{h \to 0}\frac{f(a + 2h) - f(a - h)}{h} are handled by subtracting and adding f(a)f(a), giving 3f′(a)3f'(a).

Differentiating polynomials

Rules
(xn)′=nxn−1,(c)′=0,{kf(x)+lg(x)}′=kf′(x)+lg′(x)(x^n)' = nx^{n-1},\qquad (c)' = 0,\qquad \{kf(x) + lg(x)\}' = kf'(x) + lg'(x)

Differentiate term by term; expand products such as (2x+1)(x−3)(2x + 1)(x - 3) first. Example: (x3−4x2+5)′=3x2−8x(x^3 - 4x^2 + 5)' = 3x^2 - 8x.

The same rules apply to other variables: the area of a circle S=πr2S = \pi r^2 has dSdr=2πr\frac{dS}{dr} = 2\pi r, the circumference.

Tangent and normal lines

Tangent and normal

At the point (a, f(a))(a,\ f(a)) on y=f(x)y = f(x):

tangent:y−f(a)=f′(a)(x−a),normal:y−f(a)=−1f′(a)(x−a)\text{tangent}: y - f(a) = f'(a)(x - a),\qquad \text{normal}: y - f(a) = -\frac{1}{f'(a)}(x - a)

For a tangent drawn from a point not on the curve, let the point of contact be at x=tx = t, write the tangent, and require it to pass through the given point.

Tangents to cubics

Eliminating yy between a cubic and its tangent at x=ax = a gives a cubic equation with the factor (x−a)2(x - a)^2; the remaining factor gives the other common point.