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Math C

The Complex Plane: Practice Problems

In polar form, multiplication by a complex number is a rotation combined with a scaling. Practise De Moivre's theorem and the rotation formula.

Basic, Standard: Grade 12 · Term 1 / Advanced: Grade 12 · Exam prep

Math problem generator

Level

Absolute value, argument and polar form

For z=a+biz = a + bi, ∣z∣=a2+b2|z| = \sqrt{a^2 + b^2}. Writing z=r(cos⁡θ+isin⁡θ)z = r(\cos\theta + i\sin\theta) with r=∣z∣r = |z| is the polar form, and θ\theta is the argument.

Products and quotients
∣z1z2∣=∣z1∣∣z2∣,arg⁡z1z2=arg⁡z1+arg⁡z2,∣z1z2∣=∣z1∣∣z2∣,arg⁡z1z2=arg⁡z1−arg⁡z2|z_1z_2| = |z_1||z_2|,\quad \arg z_1z_2 = \arg z_1 + \arg z_2,\qquad \left|\frac{z_1}{z_2}\right| = \frac{|z_1|}{|z_2|},\quad \arg\frac{z_1}{z_2} = \arg z_1 - \arg z_2

De Moivre's theorem and n-th roots

De Moivre's theorem
(cos⁡θ+isin⁡θ)n=cos⁡nθ+isin⁡nθ(\cos\theta + i\sin\theta)^n = \cos n\theta + i\sin n\theta

To solve zn=wz^n = w, put z=r(cos⁡θ+isin⁡θ)z = r(\cos\theta + i\sin\theta) and compare absolute values and arguments, allowing the argument to differ by 2kπ2k\pi. Taking k=0,1,…,n−1k = 0, 1, \ldots, n - 1 gives the nn solutions.

Rotations and geometry

Rotating β\beta about α\alpha by θ\theta gives γ\gamma with

γ−α=(β−α)(cos⁡θ+isin⁡θ).\gamma - \alpha = (\beta - \alpha)(\cos\theta + i\sin\theta).

In polar form, γ−αβ−α\dfrac{\gamma - \alpha}{\beta - \alpha} has absolute value ACAB\dfrac{\mathrm{AC}}{\mathrm{AB}} and argument ∠BAC\angle \mathrm{BAC}, which reveals the shape of the triangle.

Loci

∣z−α∣=r|z - \alpha| = r is a circle, ∣z−α∣=∣z−β∣|z - \alpha| = |z - \beta| is the perpendicular bisector, and ∣z−α∣=k∣z−β∣ (k≠1)|z - \alpha| = k|z - \beta|\ (k \neq 1) is a circle (the Apollonius circle).