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Math I

Linear Inequalities: Practice Problems and Methods

Linear inequalities are solved much like linear equations, except that multiplying or dividing by a negative number reverses the inequality.

Basic, Standard, Advanced: Grade 10 · Term 1

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Linear inequalities and systems

Properties

If A<BA < B, then A+C<B+CA + C < B + C; if C>0C > 0, AC<BCAC < BC; if C<0C < 0, AC>BCAC > BC (the inequality reverses).

Example: 3x−4<5x+23x - 4 < 5x + 2 gives −2x<6-2x < 6, so x>−3x > -3 (dividing by −2-2 reverses the sign).

For a system, solve each inequality and take the overlap on a number line. If there is no overlap, there is no solution. Clear fractions or decimals first by multiplying by a common denominator or by 10.

Equations and inequalities with absolute values

For c>0c > 0
∣x∣=c  ⟺  x=±c,∣x∣<c  ⟺  −c<x<c,∣x∣>c  ⟺  x<−c or x>c|x| = c \iff x = \pm c,\qquad |x| < c \iff -c < x < c,\qquad |x| > c \iff x < -c \text{ or } x > c

With two absolute values, as in ∣x−1∣+∣x−3∣<4|x - 1| + |x - 3| < 4, or with xx on the right, as in ∣x−2∣=2x+1|x - 2| = 2x + 1, split into cases at the points where the expressions inside become 0. Always check that each solution lies in the range of its case.

Counting integer solutions; word problems

For a problem such as "x>2x > 2 and x<ax < a have exactly 3 integer solutions", the integers must be 3,4,53, 4, 5 but not 66. Test the boundary values a=5a = 5 and a=6a = 6 directly to decide whether equality is allowed (the answer is 5<a≦65 < a \leqq 6).

Word problems

Let xx be the unknown, write an inequality, solve it, and then apply conditions such as "xx is a whole number". Pay attention to "at least", "more than", "at most" and "less than".