Teleport

Main features

On this page

Topics

Arithmetic drills
Grade 7
Grade 8
Grade 9
Math I
Math A
Math II
Math B
Math C
Math III
Calculus
Linear algebra
Differential equations

Display

Theme
Math II

Circles, loci and regions: practice problems

Every circle problem starts with the centre and the radius. The distance from the centre to a line is the other key idea.

Basic, Standard: Grade 11 · Term 1 / Advanced: Grade 12 · Exam prep

See it on the graph

Math problem generator

Level

Equations of circles

Equation of a circle
(x−a)2+(y−b)2=r2(centre (a, b), radius r)(x - a)^2 + (y - b)^2 = r^2 \quad (\text{centre } (a,\ b),\ \text{radius } r)

The expanded form x2+y2+lx+my+n=0x^2 + y^2 + lx + my + n = 0 is called the general form.

To read off the centre and radius from the general form, complete the square in xx and in yy. For a circle through three points, substitute the points into the general form and solve for ll, mm, nn.

Circles and lines; tangents

Let dd be the distance from the centre to a line and rr the radius: the line cuts the circle twice if d<rd < r, touches it if d=rd = r, and misses it if d>rd > r.

Tangent formula

The tangent to x2+y2=r2x^2 + y^2 = r^2 at (x1, y1)(x_1,\ y_1) is x1x+y1y=r2x_1x + y_1y = r^2.

A chord at distance dd from the centre has length 2r2−d22\sqrt{r^2 - d^2}. Subtracting the equations of two intersecting circles gives the line through their intersection points.

Loci

To find a locus, let P =(x, y)= (x,\ y), write the condition as an equation in xx and yy, and identify the curve.

Example: points P with PA:PB=2:1\mathrm{PA} : \mathrm{PB} = 2 : 1 for A(0, 0)(0,\ 0), B(3, 0)(3,\ 0) satisfy PA2=4PB2\mathrm{PA}^2 = 4\mathrm{PB}^2, i.e. (x−4)2+y2=4(x - 4)^2 + y^2 = 4: a circle with centre (4, 0)(4,\ 0) and radius 22 (a circle of Apollonius).

If P depends on a moving point Q =(s, t)= (s,\ t), express ss and tt in terms of xx and yy and substitute into the condition on Q.

Regions and maximum or minimum values

y>mx+ny > mx + n is the region above a line, and (x−a)2+(y−b)2<r2(x - a)^2 + (y - b)^2 < r^2 is the inside of a circle.

To maximise ax+byax + by over a region, set ax+by=kax + by = k: this is a line, and you want the largest kk for which it still meets the region. For a polygonal region the extreme values occur at vertices.